Schrödinger Equation

The transmission of electrons through a thin barrier provides an introduction to the equation that governs how a wave function changes with time.

平均1 eVの電子が厚さ0.2 nm・高さ2 eVの壁を透過する確率は?

The equations explain the phenomenon

  1. 1A free electron is represented by a wave.ψ=⁠ei(kx − ωt)⁠,p = ħk,E = ħω……
  2. 2Differentiation reveals the connection to momentum and energy.−iħ ∂ψ∂x = p ψ⁠,iħ ∂ψ∂t = E ψ……
  3. 3The fundamental equation of quantum mechanics is introduced.iħ ∂ψ∂t=⁠−(ħ²2m) ∂²ψ∂x²+⁠V ψ……
  4. 4The wave function determines the probability density for position.Probability density for position=⁠|ψ|²……
  5. 5Superposing waves produces a moving wave packet.Speed of the wave packet's center=⁠Mean momentumm……
  6. 6Stationary states have probability densities that do not change with time.−(ħ²2m) φ″ + V φ=⁠E φ……
  7. 7The wave function and its slope are matched at both edges of the barrier.φ and φ′ are continuous.(x = 0,a)……
  8. 8The 4 equations determine the transmission amplitude t.t=⁠e−ikacosh κa + i g sinh κa……
  9. 9The ratio of probability currents determines the transmission probability.Transmission probability T=⁠1cosh²(κa)(Wave with definite E, V₀ = 2E)……
  10. Returning to the motion in the opening example, ψ(x, t) is obtained by multiplying each energy state by e−iEt/ħ and adding the states with their respective weights. Its |ψ|² forms the moving peak in the diagram above.Once the waves are far from the barrier, the area on the right equals the average transmission probability in step 9.
  11. Further study: An electron in a box
  12. 10A particle is confined in a box.φn = √(2L) sin(nπxL)⁠,En = n² h²8 m L²……
  13. 11The lowest energy of an electron in a box of length 1 nm is calculated.E₁=⁠0.376 eV……