Waves Can Be Represented as Superpositions of Sine Waves.

The shape of a plucked string is represented as a sum of sine waves. The convergence as more terms are added is then compared for a continuous shape and a shape with jumps in height.

項数を20から1000へ増やすと、行きすぎは跳びの高さの何%に近づくか?

The equations explain the phenomenon

  1. 1A point on a circle can be represented by 1 number.eiθ=⁠cosθ + i sinθ……
  2. 2Differentiation can be represented by multiplication.ddt eiωt=⁠iω eiωt……
  3. 3The string has a set of normal modes.yn=⁠sin(nπxL) cos(ωn t)……
  4. 4Superposition produces the desired shape.SN(x)=⁠Σn=1N bn sin(nπxL)……
  5. 5Sine waves of different orders are orthogonal.∫0Lsin(nπxL)sin(mπxL)dx=⁠(L2) δnm……
  6. 6The coefficient bn can be isolated.bn=⁠(2L) ∫0Lf(x) sin(nπxL) dx……
  7. The calculations from this point use the dimensionless coordinate ξ = x/L, obtained by dividing position by the length L.The equations in Steps 7–10 use ξ. Since L = 1 m, the value of ξ equals the numerical value of x measured in m. The horizontal axis of each graph remains x [m].
  8. 7The coefficients for a plucked string can be calculated.bn=⁠8h sin(nπ/2)n²π²……
  9. The following sections consider functions with jumps in height, rather than the string itself (displacement is continuous in the small-slope string model). Only the triangle in Step 7 is referred to as a string shape.
  10. 8The coefficients for a shape with jumps can be calculated.bn=⁠(2nπ)[cos(nπ/4)− cos(3nπ/4)]……
  11. 9The peak height near a jump can be calculated.For large NPeak height of SN≒⁠12 + Si(π)π ≒ 1.0895……
  12. 10An error bound can be found for the shape with straight ramps replacing the jumps.|SN − f|≦8aπ² N……
  13. Further study: the time evolution of a string and the Fourier transform
  14. 11Each component evolves in time.y(x, t)=⁠½[F(x − ct) + F(x + ct)]……
  15. 12A short signal can be represented as a sum over continuous frequencies.Δt · Δω=⁠1 (Gaussian width)……