Prerequisite materialSchrödinger EquationThe Nature of Force

A Force Acting on a Wave Packet Leads to the Equation of Motion.

We calculate the motion of an electron in an electric field using only the Schrödinger equation and compare the center of its wave packet with the solution of the equation of motion.

波の計算の結果は、運動方程式の答えとどれだけ違うか

The equations explain the phenomenon

  1. 1We obtain the wave relation in the absence of a force.ħω=⁠ħ²k²2m……
  2. 2Superposing waves produces a wave packet.ψ(x, t)=⁠∫ A(k) ei(kx − ωt) dk……
  3. 3We find the speed of the wave packet.v=⁠dωdk=⁠ħkm……
  4. 4We express the speed in terms of momentum.v=⁠pm……
  5. 5We introduce a force.iħ ∂ψ∂t=⁠−(ħ²2m) ∂²ψ∂x²− F x ψ……
  6. 6The force term rotates the wave's phase at a rate that depends on position.ψ→⁠ψ × eiFxt/ħ……
  7. 7The wavenumber increases with time.k(t)=⁠k₀+⁠Ftħ……
  8. 8Force changes momentum.dpdt=⁠F……
  9. 9The equation of motion follows.mdvdt=⁠F……
  10. The following section considers forces that vary with position.
  11. 10We derive the equation for the average when the force varies with position.d⟨p⟩dt=⁠⟨F(x)⟩⁠,d⟨x⟩dt = ⟨p⟩m……
  12. 11For a narrow wave packet, the average force approaches the force at its center.m d²⟨x⟩dt²≒⁠F(⟨x⟩)+⁠½ F″(⟨x⟩) σ²……
  13. 12For a spring, the forces agree regardless of the packet width.F = −kx⇒⁠F″ = 0……
  14. 13At a narrow barrier, the motion departs from the equation of motion.σ≳Distance over which the force varies⇒⁠The wave packet splits into 2 parts.……
  15. 14Wave packets of massive objects spread negligibly.Spreading time≒⁠2mσ²ħ……