Prerequisite materialSimple Harmonic Motion

Damped Oscillation, Forced Oscillation, and Resonance

A periodic external force with an amplitude of 0.20 N acts on a 1.0 kg object attached to a spring with a spring constant of 4.0 N/m.

十分時間がたつと、振幅は一定の力F₀による伸びF₀/kの何倍か?

The equations explain the phenomenon

  1. 1A damping force and a periodic external force are included.m d²xdt²=⁠−k x− b dxdt+ F₀ cos ωt……
  2. The motion of the system is the sum x = xfree + xforced, where xfree solves the equation without the external force and xforced is the steady-state oscillation at the driving angular frequency. Step 10 explains why the solutions can be added.The component xfree accounts for the difference between the initial position and velocity and those of the steady-state oscillation. The system's initial position of 0 and initial velocity of 0 are not applied directly to xfree. The end of Step 4 explains how its coefficients are determined.
  3. 2An exponential function is substituted into the equation without the external force.x = eλt⇒⁠m λ² + b λ + k = 0……
  4. 3The solutions fall into 3 cases according to the damping strength.λ=⁠−γ ± √(γ² − ω₀²)……
  5. 4A solution at the driving angular frequency is found.xforced = Re(A eiωt)⇒⁠(k − mω² + i b ω) A = F₀……
  6. 5The amplitude is determined.|A|=⁠F₀√((k − mω²)² + (bω)²)……
  7. 6The system is driven at its natural angular frequency.|A|=⁠F₀b ω₀……
  8. 7The phase lag of the displacement relative to the external force is determined.tan δ=⁠2γωω₀² − ω²……
  9. 8Numerical calculations show the transition to steady-state oscillation.x(t)→⁠|A| cos(ωt − δ)……
  10. 9Q measures how weak the damping is.Q=⁠ω₀2γ=⁠kb ω₀……
  11. Further study: motion under multiple external forces
  12. 10The solution without the external force and the steady-state solution are added.x=⁠xfree+⁠xforced……