Prerequisite materialThe Lagrangian and the Condition for Stationary ActionWhy Momentum Is Conserved

Symmetry and Conservation Laws

A spring between objects of mass 1 kg and 3 kg on a frictionless floor is compressed and released with both objects initially at rest.

自然長に戻ったとき、3 kgの速さは1 kgの何倍か?

The equations explain the phenomenon

  1. 1Consider the case where L does not depend on position∂L∂x = 0⇒⁠p = ∂L∂x = constant……
  2. 2Write the Lagrangian L for the 2 objectsL=⁠½ m₁ x₁² + ½ m₂ x₂²− U(x₂ − x₁)……
  3. 3The 2 objects are displaced by the same distance a in the same directionx₁ → x₁ + a,x₂ → x₂ + a⇒⁠∂L∂x₁ + ∂L∂x₂ = 0……
  4. 4The Euler–Lagrange equations for the 2 objects are addedd(p₁ + p₂)dt=⁠0……
  5. 5The result applies to 2 objects initially at restm₁ v₁ + m₂ v₂=⁠0⇒⁠|v₂||v₁| = m₁m₂……
  6. 6A candidate conserved quantity H is defined and its time dependence is examineddHdt=⁠p x + p x− (∂L∂x) x− (∂L∂x) x− ∂L∂t……
  7. 7The canceling terms are eliminated∂L∂t = 0⇒⁠H = ∑ᵢ pᵢ xᵢ − L = constant……
  8. 8Conservation of momentum and energy determines the 2 speeds½ k d²=⁠½ m₁ v₁² + ½ m₂ v₂²……
  9. 9The object on the right is fixed to the floorWith the right object fixed:p₁ + p₂ is not constant⁠,Conservation of energy gives½ m₁ v₁² = ½ k d²……
  10. Further topics: rotational symmetry, external work, phase, and friction
  11. 10L is invariant under rotation∂L∂θ = 0⇒⁠m r² θ = constant……
  12. 11The spring constant varies with timek(t) = k₀(1 + ε cos 2ω₀t)⇒⁠dHdt = ½ (dkdt) x²⁠,Generally nonzero……
  13. 12The symmetries correspond to conserved quantitiesContinuous symmetry→⁠Corresponding conserved quantity……
  14. 13The wave's phase is shiftedFor the Schrödinger field:Phase symmetry of the action→⁠Conservation of total probability……
  15. 14The case with friction is revisitedMechanical Energy→⁠Internal energy of the floor and objects……