Prerequisite materialThe Nature of Force

Conditions for conservation of mechanical energy

First, consider the case without friction. A small object released from rest on a fixed, smooth rail passes through the bottom and climbs the slope on the opposite side.

高さ1.0 mから放すと、反対側ではどの高さまで上がるか?

The equations explain the phenomenon

  1. 1The derivation begins with the equation of motionmdvdt=⁠F……
  2. 2Both sides are multiplied by the velocity.mvdvdt=⁠Fv……
  3. 3The left-hand side is expressed as a time derivative.d(½mv²)dt=⁠Fv……
  4. 4Velocity is expressed as the time derivative of position.d(½mv²)dt=⁠Fdxdt……
  5. 5Force is expressed as a derivative of potential energy.d(½mv²)dt=⁠−(dUdx)dxdt……
  6. 6The right-hand side is expressed as a time derivative.d(½mv²)dt=⁠−dUdt……
  7. 7Adding dU/dt to both sides combines the terms into the time derivative of the total energy.d(½mv² + U)dt=⁠0……
  8. 8We identify the quantity that remains unchanged with time.½mv² + U=⁠Constant……
  9. 9The condition for conservation is applied to motion along the rail.m dvdt=⁠−m g sinθ=⁠−d(m g y)ds……
  10. 10Conservation of mechanical energy equates the energy at release to the energy at the highest point.ymax=⁠h₀……
  11. With friction: calculate the decrease in mechanical energy.
  12. 11The decrease in energy is calculated from the work done by friction.ymax=⁠h₀−⁠μ L……